When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c + = 5c + y - 6 for c in terms of y.
| \(\frac{1}{3}\)y - 2 | |
| -\(\frac{2}{5}\)y + 1\(\frac{4}{5}\) | |
| 8y + 7 | |
| -1\(\frac{2}{11}\)y + \(\frac{1}{11}\) |