When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 2c - 4c = -9c - 3z + 6 for c in terms of z.
| -\(\frac{3}{13}\)z - \(\frac{5}{13}\) | |
| \(\frac{1}{11}\)z + \(\frac{6}{11}\) | |
| -7z - 8 | |
| 1\(\frac{4}{5}\)z - 1 |