When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 2c + = -c + z + 1 for c in terms of z.
| 3z - 1\(\frac{3}{5}\) | |
| 6z - 8 | |
| \(\frac{1}{10}\)z + \(\frac{1}{5}\) | |
| \(\frac{1}{3}\)z + \(\frac{1}{3}\) |