When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c - 3c = 5c + 4z + 8 for c in terms of z.
| 2\(\frac{1}{3}\)z + 2\(\frac{2}{3}\) | |
| 5\(\frac{2}{3}\)z - \(\frac{1}{3}\) | |
| \(\frac{1}{7}\)z + \(\frac{1}{14}\) | |
| \(\frac{8}{13}\)z - \(\frac{3}{13}\) |