ASVAB Math Knowledge Practice Test 319663 Results

Your Results Global Average
Questions 5 5
Correct 0 3.16
Score 0% 63%

Review

1

The endpoints of this line segment are at (-2, -3) and (2, -1). What is the slope-intercept equation for this line?

41% Answer Correctly
y = \(\frac{1}{2}\)x - 2
y = \(\frac{1}{2}\)x + 3
y = 2x + 3
y = 2\(\frac{1}{2}\)x - 3

Solution

The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is -2. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -3) and (2, -1) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-1.0) - (-3.0)}{(2) - (-2)} \) = \( \frac{2}{4} \)
m = \(\frac{1}{2}\)

Plugging these values into the slope-intercept equation:

y = \(\frac{1}{2}\)x - 2


2

If the area of this square is 49, what is the length of one of the diagonals?

68% Answer Correctly
\( \sqrt{2} \)
7\( \sqrt{2} \)
3\( \sqrt{2} \)
8\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{49} \) = 7

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 72 + 72
c2 = 98
c = \( \sqrt{98} \) = \( \sqrt{49 x 2} \) = \( \sqrt{49} \) \( \sqrt{2} \)
c = 7\( \sqrt{2} \)


3

Breaking apart a quadratic expression into a pair of binomials is called:

75% Answer Correctly

normalizing

squaring

factoring

deconstructing


Solution

To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.


4

What is 5a + 2a?

81% Answer Correctly
a2
10a
3a2
7a

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

5a + 2a = 7a


5

The dimensions of this cylinder are height (h) = 5 and radius (r) = 7. What is the surface area?

48% Answer Correctly
168π
100π
120π
112π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(72) + 2π(7 x 5)
sa = 2π(49) + 2π(35)
sa = (2 x 49)π + (2 x 35)π
sa = 98π + 70π
sa = 168π