When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 9c + 5c = -3c + 3x - 3 for c in terms of x.
| 6x + 3\(\frac{1}{2}\) | |
| 2x + 1 | |
| -\(\frac{1}{6}\)x - \(\frac{1}{4}\) | |
| x + 2\(\frac{2}{3}\) |