ASVAB Math Knowledge Practice Test 322394 Results

Your Results Global Average
Questions 5 5
Correct 0 3.23
Score 0% 65%

Review

1

A quadrilateral is a shape with __________ sides.

91% Answer Correctly

2

5

3

4


Solution

A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.


2

Which of the following statements about a parallelogram is not true?

50% Answer Correctly

opposite sides and adjacent angles are equal

the perimeter of a parallelogram is the sum of the lengths of all sides

a parallelogram is a quadrilateral

the area of a parallelogram is base x height


Solution

A parallelogram is a quadrilateral with two sets of parallel sides. Opposite sides (a = c, b = d) and angles (red = red, blue = blue) are equal. The area of a parallelogram is base x height and the perimeter is the sum of the lengths of all sides (a + b + c + d).


3

What is 8a + 9a?

81% Answer Correctly
a2
72a
17a
72a2

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

8a + 9a = 17a


4

Which of the following statements about a triangle is not true?

57% Answer Correctly

sum of interior angles = 180°

perimeter = sum of side lengths

area = ½bh

exterior angle = sum of two adjacent interior angles


Solution

A triangle is a three-sided polygon. It has three interior angles that add up to 180° (a + b + c = 180°). An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite (d = b + c). The perimeter of a triangle is equal to the sum of the lengths of its three sides, the height of a triangle is equal to the length from the base to the opposite vertex (angle) and the area equals one-half triangle base x height: a = ½ base x height.


5

Solve for y:
-4y + 8 > \( \frac{y}{-7} \)

44% Answer Correctly
y > -\(\frac{40}{41}\)
y > 2\(\frac{2}{27}\)
y > 2\(\frac{7}{19}\)
y > 2\(\frac{1}{2}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.

-4y + 8 > \( \frac{y}{-7} \)
-7 x (-4y + 8) > y
(-7 x -4y) + (-7 x 8) > y
28y - 56 > y
28y - 56 - y > 0
28y - y > 56
27y > 56
y > \( \frac{56}{27} \)
y > 2\(\frac{2}{27}\)