| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.23 |
| Score | 0% | 65% |
A quadrilateral is a shape with __________ sides.
2 |
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5 |
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3 |
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4 |
A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.
Which of the following statements about a parallelogram is not true?
opposite sides and adjacent angles are equal |
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the perimeter of a parallelogram is the sum of the lengths of all sides |
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a parallelogram is a quadrilateral |
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the area of a parallelogram is base x height |
A parallelogram is a quadrilateral with two sets of parallel sides. Opposite sides (a = c, b = d) and angles (red = red, blue = blue) are equal. The area of a parallelogram is base x height and the perimeter is the sum of the lengths of all sides (a + b + c + d).
What is 8a + 9a?
| a2 | |
| 72a | |
| 17a | |
| 72a2 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
8a + 9a = 17a
Which of the following statements about a triangle is not true?
sum of interior angles = 180° |
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perimeter = sum of side lengths |
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area = ½bh |
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exterior angle = sum of two adjacent interior angles |
A triangle is a three-sided polygon. It has three interior angles that add up to 180° (a + b + c = 180°). An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite (d = b + c). The perimeter of a triangle is equal to the sum of the lengths of its three sides, the height of a triangle is equal to the length from the base to the opposite vertex (angle) and the area equals one-half triangle base x height: a = ½ base x height.
Solve for y:
-4y + 8 > \( \frac{y}{-7} \)
| y > -\(\frac{40}{41}\) | |
| y > 2\(\frac{2}{27}\) | |
| y > 2\(\frac{7}{19}\) | |
| y > 2\(\frac{1}{2}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
-4y + 8 > \( \frac{y}{-7} \)
-7 x (-4y + 8) > y
(-7 x -4y) + (-7 x 8) > y
28y - 56 > y
28y - 56 - y > 0
28y - y > 56
27y > 56
y > \( \frac{56}{27} \)
y > 2\(\frac{2}{27}\)