| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.60 |
| Score | 0% | 52% |
The endpoints of this line segment are at (-2, 1) and (2, 3). What is the slope of this line?
| 1 | |
| 1\(\frac{1}{2}\) | |
| \(\frac{1}{2}\) | |
| 3 |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 1) and (2, 3) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(3.0) - (1.0)}{(2) - (-2)} \) = \( \frac{2}{4} \)Simplify (8a)(9ab) - (8a2)(9b).
| b2 | |
| 144ab2 | |
| 0a2b | |
| 2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(8a)(9ab) - (8a2)(9b)
(8 x 9)(a x a x b) - (8 x 9)(a2 x b)
(72)(a1+1 x b) - (72)(a2b)
72a2b - 72a2b
0a2b
If side a = 4, side b = 6, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{65} \) | |
| \( \sqrt{61} \) | |
| \( \sqrt{52} \) | |
| \( \sqrt{10} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 42 + 62
c2 = 16 + 36
c2 = 52
c = \( \sqrt{52} \)
A cylinder with a radius (r) and a height (h) has a surface area of:
2(π r2) + 2π rh |
|
π r2h |
|
π r2h2 |
|
4π r2 |
A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.
Solve -7a - 8a = 6a + 9y - 8 for a in terms of y.
| y + 1 | |
| -1\(\frac{4}{13}\)y + \(\frac{8}{13}\) | |
| -11y - 1 | |
| 1\(\frac{2}{5}\)y + \(\frac{2}{5}\) |
To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.
-7a - 8y = 6a + 9y - 8
-7a = 6a + 9y - 8 + 8y
-7a - 6a = 9y - 8 + 8y
-13a = 17y - 8
a = \( \frac{17y - 8}{-13} \)
a = \( \frac{17y}{-13} \) + \( \frac{-8}{-13} \)
a = -1\(\frac{4}{13}\)y + \(\frac{8}{13}\)