ASVAB Math Knowledge Practice Test 323584 Results

Your Results Global Average
Questions 5 5
Correct 0 2.60
Score 0% 52%

Review

1

The endpoints of this line segment are at (-2, 1) and (2, 3). What is the slope of this line?

46% Answer Correctly
1
1\(\frac{1}{2}\)
\(\frac{1}{2}\)
3

Solution

The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 1) and (2, 3) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(3.0) - (1.0)}{(2) - (-2)} \) = \( \frac{2}{4} \)
m = \(\frac{1}{2}\)


2

Simplify (8a)(9ab) - (8a2)(9b).

62% Answer Correctly
b2
144ab2
0a2b
2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(8a)(9ab) - (8a2)(9b)
(8 x 9)(a x a x b) - (8 x 9)(a2 x b)
(72)(a1+1 x b) - (72)(a2b)
72a2b - 72a2b
0a2b


3

If side a = 4, side b = 6, what is the length of the hypotenuse of this right triangle?

64% Answer Correctly
\( \sqrt{65} \)
\( \sqrt{61} \)
\( \sqrt{52} \)
\( \sqrt{10} \)

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 42 + 62
c2 = 16 + 36
c2 = 52
c = \( \sqrt{52} \)


4

A cylinder with a radius (r) and a height (h) has a surface area of:

54% Answer Correctly

2(π r2) + 2π rh

π r2h

π r2h2

4π r2


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.


5

Solve -7a - 8a = 6a + 9y - 8 for a in terms of y.

34% Answer Correctly
y + 1
-1\(\frac{4}{13}\)y + \(\frac{8}{13}\)
-11y - 1
1\(\frac{2}{5}\)y + \(\frac{2}{5}\)

Solution

To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.

-7a - 8y = 6a + 9y - 8
-7a = 6a + 9y - 8 + 8y
-7a - 6a = 9y - 8 + 8y
-13a = 17y - 8
a = \( \frac{17y - 8}{-13} \)
a = \( \frac{17y}{-13} \) + \( \frac{-8}{-13} \)
a = -1\(\frac{4}{13}\)y + \(\frac{8}{13}\)