ASVAB Math Knowledge Practice Test 324428

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 3c + 3c = -6c - 9y - 8 for c in terms of y.

-1\(\frac{5}{6}\)y + \(\frac{1}{2}\)
-1\(\frac{1}{3}\)y - \(\frac{8}{9}\)
-2\(\frac{1}{4}\)y - 1\(\frac{1}{4}\)
2\(\frac{2}{7}\)y - 1\(\frac{2}{7}\)