When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c + 3c = -2c + 8y - 1 for c in terms of y.
| 14y - 1 | |
| -1\(\frac{1}{12}\)y + \(\frac{7}{12}\) | |
| \(\frac{5}{6}\)y - \(\frac{1}{6}\) | |
| -y - \(\frac{5}{7}\) |