| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.92 |
| Score | 0% | 58% |
A cylinder with a radius (r) and a height (h) has a surface area of:
4π r2 |
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π r2h2 |
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π r2h |
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2(π r2) + 2π rh |
A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.
Breaking apart a quadratic expression into a pair of binomials is called:
squaring |
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factoring |
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deconstructing |
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normalizing |
To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.
Solve for z:
5z + 2 < \( \frac{z}{7} \)
| z < -\(\frac{7}{17}\) | |
| z < -5 | |
| z < \(\frac{42}{55}\) | |
| z < -\(\frac{3}{4}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
5z + 2 < \( \frac{z}{7} \)
7 x (5z + 2) < z
(7 x 5z) + (7 x 2) < z
35z + 14 < z
35z + 14 - z < 0
35z - z < -14
34z < -14
z < \( \frac{-14}{34} \)
z < -\(\frac{7}{17}\)
If the base of this triangle is 1 and the height is 1, what is the area?
| 98 | |
| 38\(\frac{1}{2}\) | |
| 52\(\frac{1}{2}\) | |
| \(\frac{1}{2}\) |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 1 x 1 = \( \frac{1}{2} \) = \(\frac{1}{2}\)
If side a = 5, side b = 8, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{74} \) | |
| \( \sqrt{50} \) | |
| \( \sqrt{85} \) | |
| \( \sqrt{89} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 52 + 82
c2 = 25 + 64
c2 = 89
c = \( \sqrt{89} \)