ASVAB Math Knowledge Practice Test 326216 Results

Your Results Global Average
Questions 5 5
Correct 0 3.31
Score 0% 66%

Review

1

Solve for x:
4x + 2 > \( \frac{x}{8} \)

44% Answer Correctly
x > \(\frac{36}{53}\)
x > -1\(\frac{11}{14}\)
x > -1\(\frac{29}{34}\)
x > -\(\frac{16}{31}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.

4x + 2 > \( \frac{x}{8} \)
8 x (4x + 2) > x
(8 x 4x) + (8 x 2) > x
32x + 16 > x
32x + 16 - x > 0
32x - x > -16
31x > -16
x > \( \frac{-16}{31} \)
x > -\(\frac{16}{31}\)


2

Solve for c:
c2 - c - 6 = 0

58% Answer Correctly
1 or -7
6 or -7
-2 or 3
3 or 3

Solution

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

c2 - c - 6 = 0
(c + 2)(c - 3) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (c + 2) or (c - 3) must equal zero:

If (c + 2) = 0, c must equal -2
If (c - 3) = 0, c must equal 3

So the solution is that c = -2 or 3


3

If AD = 30 and BD = 25, AB = ?

75% Answer Correctly
8
20
2
5

Solution

The entire length of this line is represented by AD which is AB + BD:

AD = AB + BD

Solving for AB:

AB = AD - BD
AB = 30 - 25
AB = 5


4

If side a = 3, side b = 7, what is the length of the hypotenuse of this right triangle?

64% Answer Correctly
\( \sqrt{58} \)
\( \sqrt{37} \)
\( \sqrt{53} \)
\( \sqrt{65} \)

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 32 + 72
c2 = 9 + 49
c2 = 58
c = \( \sqrt{58} \)


5

A quadrilateral is a shape with __________ sides.

90% Answer Correctly

3

5

2

4


Solution

A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.