| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.35 |
| Score | 0% | 67% |
Solve for y:
4y + 2 > \( \frac{y}{8} \)
| y > \(\frac{36}{53}\) | |
| y > -1\(\frac{11}{14}\) | |
| y > -1\(\frac{29}{34}\) | |
| y > -\(\frac{16}{31}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
4y + 2 > \( \frac{y}{8} \)
8 x (4y + 2) > y
(8 x 4y) + (8 x 2) > y
32y + 16 > y
32y + 16 - y > 0
32y - y > -16
31y > -16
y > \( \frac{-16}{31} \)
y > -\(\frac{16}{31}\)
Solve for b:
b2 - b - 6 = 0
| 1 or -7 | |
| 6 or -7 | |
| -2 or 3 | |
| 3 or 3 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
b2 - b - 6 = 0
(b + 2)(b - 3) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (b + 2) or (b - 3) must equal zero:
If (b + 2) = 0, b must equal -2
If (b - 3) = 0, b must equal 3
So the solution is that b = -2 or 3
If BD = 25 and AD = 30, AB = ?
| 8 | |
| 20 | |
| 2 | |
| 5 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BDIf side a = 3, side b = 7, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{58} \) | |
| \( \sqrt{37} \) | |
| \( \sqrt{53} \) | |
| \( \sqrt{65} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 32 + 72
c2 = 9 + 49
c2 = 58
c = \( \sqrt{58} \)
A quadrilateral is a shape with __________ sides.
3 |
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5 |
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2 |
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4 |
A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.