When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c + 3c = -8c - 7z - 7 for c in terms of z.
| -2\(\frac{1}{5}\)z - \(\frac{1}{5}\) | |
| -2\(\frac{1}{2}\)z + \(\frac{1}{2}\) | |
| -\(\frac{5}{6}\)z - \(\frac{7}{12}\) | |
| -\(\frac{3}{8}\)z + \(\frac{3}{8}\) |