When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve b + 3b = 2b + 2z + 1 for b in terms of z.
| -\(\frac{2}{5}\)z - \(\frac{9}{10}\) | |
| -15z + 5 | |
| z - 1 | |
| 2\(\frac{1}{2}\)z + 1\(\frac{1}{6}\) |