ASVAB Math Knowledge Practice Test 33077 Results

Your Results Global Average
Questions 5 5
Correct 0 3.14
Score 0% 63%

Review

1

Simplify 3a x 8b.

85% Answer Correctly
11ab
24a2b2
24\( \frac{a}{b} \)
24ab

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

3a x 8b = (3 x 8) (a x b) = 24ab


2

The dimensions of this cube are height (h) = 5, length (l) = 4, and width (w) = 5. What is the surface area?

51% Answer Correctly
124
286
130
210

Solution

The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):

sa = 2lw + 2wh + 2lh
sa = (2 x 4 x 5) + (2 x 5 x 5) + (2 x 4 x 5)
sa = (40) + (50) + (40)
sa = 130


3

Find the value of a:
9a + x = 3
-5a + 9x = -4

42% Answer Correctly
\(\frac{31}{86}\)
2\(\frac{5}{6}\)
-1\(\frac{4}{35}\)
-\(\frac{6}{7}\)

Solution

You need to find the value of a so solve the first equation in terms of x:

9a + x = 3
x = 3 - 9a

then substitute the result (3 - 9a) into the second equation:

-5a + 9(3 - 9a) = -4
-5a + (9 x 3) + (9 x -9a) = -4
-5a + 27 - 81a = -4
-5a - 81a = -4 - 27
-86a = -31
a = \( \frac{-31}{-86} \)
a = \(\frac{31}{86}\)


4

The formula for volume of a cube in terms of height (h), length (l), and width (w) is which of the following?

67% Answer Correctly

lw x wh + lh

h2 x l2 x w2

2lw x 2wh + 2lh

h x l x w


Solution

A cube is a rectangular solid box with a height (h), length (l), and width (w). The volume is h x l x w and the surface area is 2lw x 2wh + 2lh.


5

If the area of this square is 4, what is the length of one of the diagonals?

68% Answer Correctly
7\( \sqrt{2} \)
2\( \sqrt{2} \)
5\( \sqrt{2} \)
3\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{4} \) = 2

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 22 + 22
c2 = 8
c = \( \sqrt{8} \) = \( \sqrt{4 x 2} \) = \( \sqrt{4} \) \( \sqrt{2} \)
c = 2\( \sqrt{2} \)