| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.01 |
| Score | 0% | 60% |
The endpoints of this line segment are at (-2, -4) and (2, 0). What is the slope-intercept equation for this line?
| y = -1\(\frac{1}{2}\)x - 3 | |
| y = 1\(\frac{1}{2}\)x - 3 | |
| y = x - 2 | |
| y = -2x + 4 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is -2. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -4) and (2, 0) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(0.0) - (-4.0)}{(2) - (-2)} \) = \( \frac{4}{4} \)Plugging these values into the slope-intercept equation:
y = x - 2
What is 6a4 - 3a4?
| 3a4 | |
| 3a8 | |
| 9 | |
| 18a8 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
6a4 - 3a4 = 3a4
Which of the following statements about a triangle is not true?
sum of interior angles = 180° |
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area = ½bh |
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perimeter = sum of side lengths |
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exterior angle = sum of two adjacent interior angles |
A triangle is a three-sided polygon. It has three interior angles that add up to 180° (a + b + c = 180°). An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite (d = b + c). The perimeter of a triangle is equal to the sum of the lengths of its three sides, the height of a triangle is equal to the length from the base to the opposite vertex (angle) and the area equals one-half triangle base x height: a = ½ base x height.
Find the value of c:
-2c + x = 1
2c - 4x = -5
| -1\(\frac{3}{23}\) | |
| -2\(\frac{1}{3}\) | |
| \(\frac{1}{6}\) |
You need to find the value of c so solve the first equation in terms of x:
-2c + x = 1
x = 1 + 2c
then substitute the result (1 - -2c) into the second equation:
2c - 4(1 + 2c) = -5
2c + (-4 x 1) + (-4 x 2c) = -5
2c - 4 - 8c = -5
2c - 8c = -5 + 4
-6c = -1
c = \( \frac{-1}{-6} \)
c = \(\frac{1}{6}\)
If a = 5, b = 1, c = 3, and d = 1, what is the perimeter of this quadrilateral?
| 23 | |
| 10 | |
| 28 | |
| 22 |
Perimeter is equal to the sum of the four sides:
p = a + b + c + d
p = 5 + 1 + 3 + 1
p = 10