ASVAB Math Knowledge Practice Test 331693 Results

Your Results Global Average
Questions 5 5
Correct 0 3.32
Score 0% 66%

Review

1

If side x = 12cm, side y = 11cm, and side z = 6cm what is the perimeter of this triangle?

84% Answer Correctly
34cm
35cm
31cm
29cm

Solution

The perimeter of a triangle is the sum of the lengths of its sides:

p = x + y + z
p = 12cm + 11cm + 6cm = 29cm


2

What is 6a4 + 6a4?

74% Answer Correctly
12a4
0
12
a48

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

6a4 + 6a4 = 12a4


3

Which of the following statements about a triangle is not true?

57% Answer Correctly

exterior angle = sum of two adjacent interior angles

perimeter = sum of side lengths

sum of interior angles = 180°

area = ½bh


Solution

A triangle is a three-sided polygon. It has three interior angles that add up to 180° (a + b + c = 180°). An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite (d = b + c). The perimeter of a triangle is equal to the sum of the lengths of its three sides, the height of a triangle is equal to the length from the base to the opposite vertex (angle) and the area equals one-half triangle base x height: a = ½ base x height.


4

Which of the following expressions contains exactly two terms?

81% Answer Correctly

polynomial

monomial

quadratic

binomial


Solution

A monomial contains one term, a binomial contains two terms, and a polynomial contains more than two terms.


5

Solve -6c - 6c = -8c - 7z - 7 for c in terms of z.

34% Answer Correctly
-\(\frac{4}{7}\)z + \(\frac{2}{7}\)
-1\(\frac{1}{6}\)z + \(\frac{1}{3}\)
\(\frac{4}{5}\)z + \(\frac{1}{2}\)
-\(\frac{1}{2}\)z - 3\(\frac{1}{2}\)

Solution

To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.

-6c - 6z = -8c - 7z - 7
-6c = -8c - 7z - 7 + 6z
-6c + 8c = -7z - 7 + 6z
2c = -z - 7
c = \( \frac{-z - 7}{2} \)
c = \( \frac{-z}{2} \) + \( \frac{-7}{2} \)
c = -\(\frac{1}{2}\)z - 3\(\frac{1}{2}\)