When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -9c + c = 5c - 8z - 3 for c in terms of z.
| 3\(\frac{3}{4}\)z - 1 | |
| \(\frac{9}{14}\)z + \(\frac{3}{14}\) | |
| -5z + 3 | |
| -\(\frac{2}{3}\)z + \(\frac{7}{12}\) |