When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c - 2c = -2c - 2z + 5 for c in terms of z.
| z - \(\frac{2}{5}\) | |
| z + \(\frac{1}{2}\) | |
| -z - 1\(\frac{3}{5}\) | |
| -\(\frac{3}{8}\)z + \(\frac{3}{8}\) |