| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.17 |
| Score | 0% | 63% |
This diagram represents two parallel lines with a transversal. If w° = 40, what is the value of c°?
| 15 | |
| 40 | |
| 29 | |
| 143 |
For parallel lines with a transversal, the following relationships apply:
Applying these relationships starting with w° = 40, the value of c° is 40.
What is 8a9 + 3a9?
| 24a9 | |
| 5a18 | |
| 11a9 | |
| 11 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
8a9 + 3a9 = 11a9
Simplify (6a)(7ab) - (6a2)(9b).
| 195a2b | |
| -12a2b | |
| 96ab2 | |
| 195ab2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(6a)(7ab) - (6a2)(9b)
(6 x 7)(a x a x b) - (6 x 9)(a2 x b)
(42)(a1+1 x b) - (54)(a2b)
42a2b - 54a2b
-12a2b
Solve for c:
-8c + 1 > \( \frac{c}{-8} \)
| c > \(\frac{3}{10}\) | |
| c > -\(\frac{15}{26}\) | |
| c > -1\(\frac{9}{31}\) | |
| c > \(\frac{8}{63}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
-8c + 1 > \( \frac{c}{-8} \)
-8 x (-8c + 1) > c
(-8 x -8c) + (-8 x 1) > c
64c - 8 > c
64c - 8 - c > 0
64c - c > 8
63c > 8
c > \( \frac{8}{63} \)
c > \(\frac{8}{63}\)
If side a = 3, side b = 1, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{40} \) | |
| \( \sqrt{10} \) | |
| \( \sqrt{50} \) | |
| \( \sqrt{80} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 32 + 12
c2 = 9 + 1
c2 = 10
c = \( \sqrt{10} \)