ASVAB Math Knowledge Practice Test 336600 Results

Your Results Global Average
Questions 5 5
Correct 0 3.17
Score 0% 63%

Review

1

This diagram represents two parallel lines with a transversal. If w° = 40, what is the value of c°?

73% Answer Correctly
15
40
29
143

Solution

For parallel lines with a transversal, the following relationships apply:

  • angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°)
  • alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°)
  • all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other
  • same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°)

Applying these relationships starting with w° = 40, the value of c° is 40.


2

What is 8a9 + 3a9?

75% Answer Correctly
24a9
5a18
11a9
11

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

8a9 + 3a9 = 11a9


3

Simplify (6a)(7ab) - (6a2)(9b).

62% Answer Correctly
195a2b
-12a2b
96ab2
195ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(6a)(7ab) - (6a2)(9b)
(6 x 7)(a x a x b) - (6 x 9)(a2 x b)
(42)(a1+1 x b) - (54)(a2b)
42a2b - 54a2b
-12a2b


4

Solve for c:
-8c + 1 > \( \frac{c}{-8} \)

44% Answer Correctly
c > \(\frac{3}{10}\)
c > -\(\frac{15}{26}\)
c > -1\(\frac{9}{31}\)
c > \(\frac{8}{63}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.

-8c + 1 > \( \frac{c}{-8} \)
-8 x (-8c + 1) > c
(-8 x -8c) + (-8 x 1) > c
64c - 8 > c
64c - 8 - c > 0
64c - c > 8
63c > 8
c > \( \frac{8}{63} \)
c > \(\frac{8}{63}\)


5

If side a = 3, side b = 1, what is the length of the hypotenuse of this right triangle?

64% Answer Correctly
\( \sqrt{40} \)
\( \sqrt{10} \)
\( \sqrt{50} \)
\( \sqrt{80} \)

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 32 + 12
c2 = 9 + 1
c2 = 10
c = \( \sqrt{10} \)