When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3c + 9c = -5c + x - 1 for c in terms of x.
| 1\(\frac{7}{8}\)x + 1\(\frac{1}{8}\) | |
| -4x + 3 | |
| \(\frac{1}{4}\)x - \(\frac{3}{8}\) | |
| -x - \(\frac{1}{8}\) |