ASVAB Math Knowledge Practice Test 337588 Results

Your Results Global Average
Questions 5 5
Correct 0 3.42
Score 0% 68%

Review

1

Which of the following is not a part of PEMDAS, the acronym for math order of operations?

91% Answer Correctly

division

exponents

addition

pairs


Solution

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)


2

Which of the following is not required to define the slope-intercept equation for a line?

42% Answer Correctly

slope

y-intercept

\({\Delta y \over \Delta x}\)

x-intercept


Solution

A line on the coordinate grid can be defined by a slope-intercept equation: y = mx + b. For a given value of x, the value of y can be determined given the slope (m) and y-intercept (b) of the line. The slope of a line is change in y over change in x, \({\Delta y \over \Delta x}\), and the y-intercept is the y-coordinate where the line crosses the vertical y-axis.


3

If a = 6 and z = -8, what is the value of 7a(a - z)?

69% Answer Correctly
450
-462
588
-24

Solution

To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

7a(a - z)
7(6)(6 + 8)
7(6)(14)
(42)(14)
588


4

Breaking apart a quadratic expression into a pair of binomials is called:

75% Answer Correctly

normalizing

factoring

squaring

deconstructing


Solution

To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.


5

If side a = 9, side b = 1, what is the length of the hypotenuse of this right triangle?

64% Answer Correctly
\( \sqrt{82} \)
\( \sqrt{98} \)
\( \sqrt{37} \)
\( \sqrt{45} \)

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 92 + 12
c2 = 81 + 1
c2 = 82
c = \( \sqrt{82} \)