When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -7b - 5b = 8b + 3z + 1 for b in terms of z.
| 2\(\frac{3}{4}\)z - 1\(\frac{1}{2}\) | |
| 1\(\frac{2}{3}\)z + \(\frac{5}{6}\) | |
| 12z + 1 | |
| -\(\frac{8}{15}\)z - \(\frac{1}{15}\) |