ASVAB Math Knowledge Practice Test 339723

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 2a - 3a = 3a - 3z - 1 for a in terms of z.

z + 1
-\(\frac{1}{2}\)z + 4\(\frac{1}{2}\)
4z - 8
-\(\frac{3}{5}\)z - 1\(\frac{1}{5}\)