ASVAB Math Knowledge Practice Test 340025

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -8c - 2c = 2c - 8y + 4 for c in terms of y.

\(\frac{3}{5}\)y - \(\frac{2}{5}\)
\(\frac{1}{14}\)y + \(\frac{1}{7}\)
1\(\frac{3}{4}\)y + \(\frac{1}{4}\)
\(\frac{2}{3}\)y - 2\(\frac{1}{3}\)