When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -3c - 2c = c + 4z + 5 for c in terms of z.
| \(\frac{15}{16}\)z - \(\frac{1}{16}\) | |
| \(\frac{1}{12}\)z - \(\frac{2}{3}\) | |
| -1\(\frac{1}{2}\)z - 1\(\frac{1}{4}\) | |
| -\(\frac{1}{4}\)z + \(\frac{5}{12}\) |