When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3c - 8c = -2c + 3y + 1 for c in terms of y.
| -7\(\frac{1}{2}\)y - 3\(\frac{1}{2}\) | |
| 2\(\frac{1}{5}\)y + \(\frac{1}{5}\) | |
| \(\frac{5}{7}\)y - 1 | |
| \(\frac{1}{13}\)y - \(\frac{6}{13}\) |