| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.54 |
| Score | 0% | 71% |
If a = c = 8, b = d = 2, what is the area of this rectangle?
| 18 | |
| 16 | |
| 28 | |
| 32 |
The area of a rectangle is equal to its length x width:
a = l x w
a = a x b
a = 8 x 2
a = 16
If the area of this square is 9, what is the length of one of the diagonals?
| \( \sqrt{2} \) | |
| 3\( \sqrt{2} \) | |
| 2\( \sqrt{2} \) | |
| 5\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{9} \) = 3
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 32 + 32
c2 = 18
c = \( \sqrt{18} \) = \( \sqrt{9 x 2} \) = \( \sqrt{9} \) \( \sqrt{2} \)
c = 3\( \sqrt{2} \)
If side a = 2, side b = 4, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{50} \) | |
| \( \sqrt{18} \) | |
| \( \sqrt{20} \) | |
| \( \sqrt{89} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 22 + 42
c2 = 4 + 16
c2 = 20
c = \( \sqrt{20} \)
The dimensions of this cube are height (h) = 5, length (l) = 9, and width (w) = 6. What is the surface area?
| 238 | |
| 106 | |
| 62 | |
| 258 |
The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):
sa = 2lw + 2wh + 2lh
sa = (2 x 9 x 6) + (2 x 6 x 5) + (2 x 9 x 5)
sa = (108) + (60) + (90)
sa = 258
A quadrilateral is a shape with __________ sides.
3 |
|
5 |
|
2 |
|
4 |
A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.