ASVAB Math Knowledge Practice Test 343597 Results

Your Results Global Average
Questions 5 5
Correct 0 3.54
Score 0% 71%

Review

1

If a = c = 8, b = d = 2, what is the area of this rectangle?

80% Answer Correctly
18
16
28
32

Solution

The area of a rectangle is equal to its length x width:

a = l x w
a = a x b
a = 8 x 2
a = 16


2

If the area of this square is 9, what is the length of one of the diagonals?

68% Answer Correctly
\( \sqrt{2} \)
3\( \sqrt{2} \)
2\( \sqrt{2} \)
5\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{9} \) = 3

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 32 + 32
c2 = 18
c = \( \sqrt{18} \) = \( \sqrt{9 x 2} \) = \( \sqrt{9} \) \( \sqrt{2} \)
c = 3\( \sqrt{2} \)


3

If side a = 2, side b = 4, what is the length of the hypotenuse of this right triangle?

64% Answer Correctly
\( \sqrt{50} \)
\( \sqrt{18} \)
\( \sqrt{20} \)
\( \sqrt{89} \)

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 22 + 42
c2 = 4 + 16
c2 = 20
c = \( \sqrt{20} \)


4

The dimensions of this cube are height (h) = 5, length (l) = 9, and width (w) = 6. What is the surface area?

51% Answer Correctly
238
106
62
258

Solution

The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):

sa = 2lw + 2wh + 2lh
sa = (2 x 9 x 6) + (2 x 6 x 5) + (2 x 9 x 5)
sa = (108) + (60) + (90)
sa = 258


5

A quadrilateral is a shape with __________ sides.

91% Answer Correctly

3

5

2

4


Solution

A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.