| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.15 |
| Score | 0% | 63% |
The formula for volume of a cube in terms of height (h), length (l), and width (w) is which of the following?
h2 x l2 x w2 |
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lw x wh + lh |
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h x l x w |
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2lw x 2wh + 2lh |
A cube is a rectangular solid box with a height (h), length (l), and width (w). The volume is h x l x w and the surface area is 2lw x 2wh + 2lh.
Which of the following expressions contains exactly two terms?
quadratic |
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monomial |
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binomial |
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polynomial |
A monomial contains one term, a binomial contains two terms, and a polynomial contains more than two terms.
Solve 9b - 4b = -9b - 3x + 5 for b in terms of x.
| x - 1\(\frac{1}{2}\) | |
| 3\(\frac{1}{3}\)x - 3 | |
| \(\frac{1}{18}\)x + \(\frac{5}{18}\) | |
| 16x - 8 |
To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.
9b - 4x = -9b - 3x + 5
9b = -9b - 3x + 5 + 4x
9b + 9b = -3x + 5 + 4x
18b = x + 5
b = \( \frac{x + 5}{18} \)
b = \( \frac{x}{18} \) + \( \frac{5}{18} \)
b = \(\frac{1}{18}\)x + \(\frac{5}{18}\)
Which of the following statements about math operations is incorrect?
you can add monomials that have the same variable and the same exponent |
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you can multiply monomials that have different variables and different exponents |
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all of these statements are correct |
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you can subtract monomials that have the same variable and the same exponent |
You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.
Factor y2 + 11y + 28
| (y + 4)(y - 7) | |
| (y + 4)(y + 7) | |
| (y - 4)(y + 7) | |
| (y - 4)(y - 7) |
To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce 28 as well and sum (Inside, Outside) to equal 11. For this problem, those two numbers are 4 and 7. Then, plug these into a set of binomials using the square root of the First variable (y2):
y2 + 11y + 28
y2 + (4 + 7)y + (4 x 7)
(y + 4)(y + 7)