| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.76 |
| Score | 0% | 55% |
Which types of triangles will always have at least two sides of equal length?
isosceles and right |
|
equilateral, isosceles and right |
|
equilateral and isosceles |
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equilateral and right |
An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.
What is the area of a circle with a diameter of 6?
| 25π | |
| 4π | |
| 6π | |
| 9π |
The formula for area is πr2. Radius is circle \( \frac{diameter}{2} \):
r = \( \frac{d}{2} \)
r = \( \frac{6}{2} \)
r = 3
a = πr2
a = π(32)
a = 9π
Solve for b:
8b + 9 < 7 + 5b
| b < -\(\frac{2}{3}\) | |
| b < \(\frac{5}{6}\) | |
| b < -\(\frac{2}{9}\) | |
| b < -\(\frac{1}{6}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
8b + 9 < 7 + 5b
8b < 7 + 5b - 9
8b - 5b < 7 - 9
3b < -2
b < \( \frac{-2}{3} \)
b < -\(\frac{2}{3}\)
The endpoints of this line segment are at (-2, -6) and (2, -2). What is the slope-intercept equation for this line?
| y = -x + 4 | |
| y = 2x + 4 | |
| y = -2x + 0 | |
| y = x - 4 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is -4. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -6) and (2, -2) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-2.0) - (-6.0)}{(2) - (-2)} \) = \( \frac{4}{4} \)Plugging these values into the slope-intercept equation:
y = x - 4
If angle a = 63° and angle b = 38° what is the length of angle d?
| 120° | |
| 133° | |
| 132° | |
| 117° |
An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite:
d° = b° + c°
To find angle c, remember that the sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 63° - 38° = 79°
So, d° = 38° + 79° = 117°
A shortcut to get this answer is to remember that angles around a line add up to 180°:
a° + d° = 180°
d° = 180° - a°
d° = 180° - 63° = 117°