ASVAB Math Knowledge Practice Test 348958 Results

Your Results Global Average
Questions 5 5
Correct 0 3.00
Score 0% 60%

Review

1

Solve for c:
c2 + 3c + 2 = 0

58% Answer Correctly
1 or -3
-1 or -2
9 or 4
7 or 7
Solution

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

c2 + 3c + 2 = 0
(c + 1)(c + 2) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (c + 1) or (c + 2) must equal zero:

If (c + 1) = 0, c must equal -1
If (c + 2) = 0, c must equal -2

So the solution is that c = -1 or -2

2

What is the area of a circle with a radius of 4?

69% Answer Correctly
2π
16π
64π
25π
Solution

The formula for area is πr2:

a = πr2
a = π(42)
a = 16π

3

What is 6a4 - 9a4?

73% Answer Correctly
-3a4
15a8
-3a8
54a8
Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

6a4 - 9a4 = -3a4

4

If BD = 15 and AD = 24, AB = ?

76% Answer Correctly
19
14
15
9
Solution

The entire length of this line is represented by AD which is AB + BD:

AD = AB + BD

Solving for AB:

AB = AD - BD
AB = 24 - 15
AB = 9

5

The formula for the area of a circle is which of the following?

24% Answer Correctly

c = π d

c = π d2

c = π r2

c = π r
Solution

The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.