| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.14 |
| Score | 0% | 63% |
Solve -4b - 7b = 3b - 3x + 2 for b in terms of x.
| -\(\frac{2}{5}\)x + 1 | |
| 2\(\frac{2}{7}\)x - \(\frac{5}{7}\) | |
| -\(\frac{4}{7}\)x - \(\frac{2}{7}\) | |
| -3x + 7 |
To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.
-4b - 7x = 3b - 3x + 2
-4b = 3b - 3x + 2 + 7x
-4b - 3b = -3x + 2 + 7x
-7b = 4x + 2
b = \( \frac{4x + 2}{-7} \)
b = \( \frac{4x}{-7} \) + \( \frac{2}{-7} \)
b = -\(\frac{4}{7}\)x - \(\frac{2}{7}\)
A quadrilateral is a shape with __________ sides.
3 |
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4 |
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2 |
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5 |
A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.
The dimensions of this cube are height (h) = 3, length (l) = 1, and width (w) = 2. What is the surface area?
| 22 | |
| 82 | |
| 72 | |
| 64 |
The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):
sa = 2lw + 2wh + 2lh
sa = (2 x 1 x 2) + (2 x 2 x 3) + (2 x 1 x 3)
sa = (4) + (12) + (6)
sa = 22
Which of the following is not a part of PEMDAS, the acronym for math order of operations?
addition |
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division |
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pairs |
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exponents |
When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
On this circle, a line segment connecting point A to point D is called:
chord |
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diameter |
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circumference |
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radius |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).