| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.73 |
| Score | 0% | 55% |
The endpoints of this line segment are at (-2, 4) and (2, 2). What is the slope of this line?
| -2 | |
| -1 | |
| 2\(\frac{1}{2}\) | |
| -\(\frac{1}{2}\) |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 4) and (2, 2) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(2.0) - (4.0)}{(2) - (-2)} \) = \( \frac{-2}{4} \)If the base of this triangle is 2 and the height is 4, what is the area?
| 84 | |
| 49\(\frac{1}{2}\) | |
| 4 | |
| 45 |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 2 x 4 = \( \frac{8}{2} \) = 4
Solve for y:
y2 + y - 19 = y - 3
| -7 or -8 | |
| 7 or -5 | |
| 4 or -4 | |
| 2 or -9 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
y2 + y - 19 = y - 3
y2 + y - 19 + 3 = y
y2 + y - y - 16 = 0
y2 - 16 = 0
Next, factor the quadratic equation:
y2 - 16 = 0
(y - 4)(y + 4) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (y - 4) or (y + 4) must equal zero:
If (y - 4) = 0, y must equal 4
If (y + 4) = 0, y must equal -4
So the solution is that y = 4 or -4
The dimensions of this cylinder are height (h) = 3 and radius (r) = 4. What is the volume?
| 50π | |
| 36π | |
| 128π | |
| 48π |
The volume of a cylinder is πr2h:
v = πr2h
v = π(42 x 3)
v = 48π
Solve for a:
6a + 2 = 4 + 9a
| -1 | |
| -\(\frac{2}{3}\) | |
| 2\(\frac{1}{4}\) | |
| -1\(\frac{1}{3}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
6a + 2 = 4 + 9a
6a = 4 + 9a - 2
6a - 9a = 4 - 2
-3a = 2
a = \( \frac{2}{-3} \)
a = -\(\frac{2}{3}\)