When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -8a + 3a = 8a - 4y - 5 for a in terms of y.
| \(\frac{7}{16}\)y + \(\frac{5}{16}\) | |
| \(\frac{1}{2}\)y - 3\(\frac{1}{2}\) | |
| \(\frac{5}{6}\)y - 1\(\frac{1}{3}\) | |
| -4\(\frac{1}{3}\)y + 2 |