When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c - 5c = -5c + x + 5 for c in terms of x.
| -1\(\frac{1}{4}\)x - 1\(\frac{1}{8}\) | |
| -2x + 2\(\frac{1}{3}\) | |
| \(\frac{10}{11}\)x - \(\frac{1}{11}\) | |
| \(\frac{6}{13}\)x + \(\frac{5}{13}\) |