When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c + 8c = 5c - 6y + 4 for c in terms of y.
| \(\frac{1}{15}\)y + \(\frac{8}{15}\) | |
| -1\(\frac{3}{5}\)y - \(\frac{3}{5}\) | |
| 14y - 4 | |
| \(\frac{3}{8}\)y + \(\frac{3}{8}\) |