| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.78 |
| Score | 0% | 56% |
If the base of this triangle is 6 and the height is 4, what is the area?
| 52 | |
| 12 | |
| 27\(\frac{1}{2}\) | |
| 71\(\frac{1}{2}\) |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 6 x 4 = \( \frac{24}{2} \) = 12
Solve for y:
-6y - 2 > 6 + 6y
| y > -\(\frac{1}{3}\) | |
| y > -2\(\frac{1}{3}\) | |
| y > -\(\frac{2}{3}\) | |
| y > \(\frac{5}{6}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
-6y - 2 > 6 + 6y
-6y > 6 + 6y + 2
-6y - 6y > 6 + 2
-12y > 8
y > \( \frac{8}{-12} \)
y > -\(\frac{2}{3}\)
If c = -4 and z = -4, what is the value of c(c - z)?
| -160 | |
| 270 | |
| -64 | |
| 0 |
To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
c(c - z)
1(-4)(-4 + 4)
1(-4)(0)
(-4)(0)
0
The endpoints of this line segment are at (-2, 2) and (2, 0). What is the slope of this line?
| -2\(\frac{1}{2}\) | |
| -1\(\frac{1}{2}\) | |
| -\(\frac{1}{2}\) | |
| 2\(\frac{1}{2}\) |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 2) and (2, 0) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(0.0) - (2.0)}{(2) - (-2)} \) = \( \frac{-2}{4} \)The dimensions of this cube are height (h) = 9, length (l) = 5, and width (w) = 9. What is the surface area?
| 342 | |
| 288 | |
| 126 | |
| 202 |
The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):
sa = 2lw + 2wh + 2lh
sa = (2 x 5 x 9) + (2 x 9 x 9) + (2 x 5 x 9)
sa = (90) + (162) + (90)
sa = 342