ASVAB Math Knowledge Practice Test 353619 Results

Your Results Global Average
Questions 5 5
Correct 0 3.29
Score 0% 66%

Review

1

Breaking apart a quadratic expression into a pair of binomials is called:

74% Answer Correctly

squaring

deconstructing

factoring

normalizing
Solution

To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.

2

When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).

61% Answer Correctly

supplementary, vertical

obtuse, acute

acute, obtuse

vertical, supplementary
Solution

Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).

3

Which of the following statements about math operations is incorrect?

70% Answer Correctly

you can add monomials that have the same variable and the same exponent

you can subtract monomials that have the same variable and the same exponent

all of these statements are correct

you can multiply monomials that have different variables and different exponents
Solution

You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.

4

If BD = 8 and AD = 12, AB = ?

76% Answer Correctly
4
16
11
1
Solution

The entire length of this line is represented by AD which is AB + BD:

AD = AB + BD

Solving for AB:

AB = AD - BD
AB = 12 - 8
AB = 4

5

For this diagram, the Pythagorean theorem states that b2 = ?

47% Answer Correctly

a2 - c2

c - a

c2 - a2

c2 + a2

Solution

The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)