When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -5b + 4b = -6b - 2z + 5 for b in terms of z.
| \(\frac{1}{3}\)z + 1 | |
| -6z + 5 | |
| -3\(\frac{1}{5}\)z + \(\frac{3}{5}\) | |
| 5\(\frac{2}{3}\)z + \(\frac{1}{3}\) |