When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -8c - 3c = 4c - 6z + 6 for c in terms of z.
| \(\frac{1}{4}\)z - \(\frac{1}{2}\) | |
| 4\(\frac{1}{3}\)z + \(\frac{2}{3}\) | |
| \(\frac{4}{9}\)z - \(\frac{2}{3}\) | |
| 1\(\frac{1}{2}\)z - 1 |