When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 5c - 2c = 4c - 8z + 5 for c in terms of z.
| 5z + 7 | |
| \(\frac{3}{16}\)z + \(\frac{1}{8}\) | |
| -6z + 5 | |
| \(\frac{2}{7}\)z - \(\frac{4}{7}\) |