| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.40 |
| Score | 0% | 68% |
If b = -1 and z = 1, what is the value of 8b(b - z)?
| 16 | |
| 25 | |
| 180 | |
| -36 |
To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
8b(b - z)
8(-1)(-1 - 1)
8(-1)(-2)
(-8)(-2)
16
The dimensions of this cube are height (h) = 6, length (l) = 3, and width (w) = 2. What is the volume?
| 135 | |
| 36 | |
| 128 | |
| 56 |
The volume of a cube is height x length x width:
v = h x l x w
v = 6 x 3 x 2
v = 36
Simplify (5a)(9ab) - (2a2)(8b).
| 61a2b | |
| -29ab2 | |
| 140a2b | |
| 29a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(5a)(9ab) - (2a2)(8b)
(5 x 9)(a x a x b) - (2 x 8)(a2 x b)
(45)(a1+1 x b) - (16)(a2b)
45a2b - 16a2b
29a2b
Which of the following is not a part of PEMDAS, the acronym for math order of operations?
exponents |
|
addition |
|
pairs |
|
division |
When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Find the value of a:
-3a + x = 5
9a - 6x = 7
| 10 | |
| \(\frac{43}{51}\) | |
| -1\(\frac{8}{9}\) | |
| -4\(\frac{1}{9}\) |
You need to find the value of a so solve the first equation in terms of x:
-3a + x = 5
x = 5 + 3a
then substitute the result (5 - -3a) into the second equation:
9a - 6(5 + 3a) = 7
9a + (-6 x 5) + (-6 x 3a) = 7
9a - 30 - 18a = 7
9a - 18a = 7 + 30
-9a = 37
a = \( \frac{37}{-9} \)
a = -4\(\frac{1}{9}\)