ASVAB Math Knowledge Practice Test 359508

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -3b + 3b = 3b - y - 4 for b in terms of y.

\(\frac{2}{3}\)y + \(\frac{2}{3}\)
-y + \(\frac{1}{2}\)
2y + 3\(\frac{1}{2}\)
-6y + 4\(\frac{1}{2}\)