When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 5c + c = 3c + 4y + 9 for c in terms of y.
| 1\(\frac{1}{2}\)y + 4\(\frac{1}{2}\) | |
| 2y + \(\frac{1}{2}\) | |
| 5y - 5 | |
| -\(\frac{1}{6}\)y + \(\frac{5}{6}\) |