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Solve -6a + 2a = -8a - 7y - 4 for a in terms of y.
| -\(\frac{1}{2}\)y - \(\frac{1}{2}\) | |
| 1\(\frac{3}{7}\)y + \(\frac{1}{7}\) | |
| -4\(\frac{1}{4}\)y - \(\frac{3}{4}\) | |
| -4\(\frac{1}{2}\)y - 2 |
To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.
-6a + 2y = -8a - 7y - 4
-6a = -8a - 7y - 4 - 2y
-6a + 8a = -7y - 4 - 2y
2a = -9y - 4
a = \( \frac{-9y - 4}{2} \)
a = \( \frac{-9y}{2} \) + \( \frac{-4}{2} \)
a = -4\(\frac{1}{2}\)y - 2
Simplify (7a)(5ab) + (7a2)(3b).
| 14ab2 | |
| 14a2b | |
| 56a2b | |
| 120a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(7a)(5ab) + (7a2)(3b)
(7 x 5)(a x a x b) + (7 x 3)(a2 x b)
(35)(a1+1 x b) + (21)(a2b)
35a2b + 21a2b
56a2b
Solve for c:
5c - 2 < \( \frac{c}{-3} \)
| c < \(\frac{3}{8}\) | |
| c < -2\(\frac{2}{17}\) | |
| c < -\(\frac{24}{73}\) | |
| c < \(\frac{32}{41}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
5c - 2 < \( \frac{c}{-3} \)
-3 x (5c - 2) < c
(-3 x 5c) + (-3 x -2) < c
-15c + 6 < c
-15c + 6 - c < 0
-15c - c < -6
-16c < -6
c < \( \frac{-6}{-16} \)
c < \(\frac{3}{8}\)
Solve for z:
-2z + 1 = -1 - z
| -3 | |
| 1\(\frac{3}{4}\) | |
| 2 | |
| -1 |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
-2z + 1 = -1 - z
-2z = -1 - z - 1
-2z + z = -1 - 1
-z = -2
z = \( \frac{-2}{-1} \)
z = 2
If the length of AB equals the length of BD, point B __________ this line segment.
intersects |
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midpoints |
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trisects |
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bisects |
A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.