When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4b - 4b = 6b + z + 1 for b in terms of z.
| -\(\frac{1}{10}\)z - \(\frac{4}{5}\) | |
| 4\(\frac{1}{3}\)z + \(\frac{1}{3}\) | |
| -\(\frac{1}{4}\)z + 2\(\frac{1}{4}\) | |
| -2\(\frac{1}{2}\)z - \(\frac{1}{2}\) |