| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.74 |
| Score | 0% | 55% |
Which of the following statements about parallel lines with a transversal is not correct?
same-side interior angles are complementary and equal each other |
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all acute angles equal each other |
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angles in the same position on different parallel lines are called corresponding angles |
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all of the angles formed by a transversal are called interior angles |
Parallel lines are lines that share the same slope (steepness) and therefore never intersect. A transversal occurs when a set of parallel lines are crossed by another line. All of the angles formed by a transversal are called interior angles and angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°) and are called corresponding angles. Alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°) and all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other. Same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°).
Simplify (y + 6)(y - 8)
| y2 + 2y - 48 | |
| y2 - 14y + 48 | |
| y2 + 14y + 48 | |
| y2 - 2y - 48 |
To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:
(y + 6)(y - 8)
(y x y) + (y x -8) + (6 x y) + (6 x -8)
y2 - 8y + 6y - 48
y2 - 2y - 48
Solve for b:
2b - 5 > -7 + b
| b > -1\(\frac{4}{5}\) | |
| b > -\(\frac{1}{4}\) | |
| b > -2 | |
| b > -\(\frac{1}{2}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
2b - 5 > -7 + b
2b > -7 + b + 5
2b - b > -7 + 5
b > -2
A trapezoid is a quadrilateral with one set of __________ sides.
equal angle |
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equal length |
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parallel |
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right angle |
A trapezoid is a quadrilateral with one set of parallel sides.
Solve for b:
b2 - 2b - 5 = -4b - 2
| 3 or -1 | |
| 5 or 1 | |
| 7 or -3 | |
| 1 or -3 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
b2 - 2b - 5 = -4b - 2
b2 - 2b - 5 + 2 = -4b
b2 - 2b + 4b - 3 = 0
b2 + 2b - 3 = 0
Next, factor the quadratic equation:
b2 + 2b - 3 = 0
(b - 1)(b + 3) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (b - 1) or (b + 3) must equal zero:
If (b - 1) = 0, b must equal 1
If (b + 3) = 0, b must equal -3
So the solution is that b = 1 or -3