When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -3b - 3b = 3b + 8y - 1 for b in terms of y.
| 2\(\frac{1}{5}\)y - 1\(\frac{2}{5}\) | |
| -1\(\frac{5}{6}\)y + \(\frac{1}{6}\) | |
| -y + 1 | |
| -3\(\frac{2}{3}\)y + 1\(\frac{2}{3}\) |