When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -6c + 4c = -c + 7z - 3 for c in terms of z.
| -z + \(\frac{1}{4}\) | |
| -\(\frac{3}{5}\)z + \(\frac{3}{5}\) | |
| -z + 3 | |
| 1\(\frac{5}{6}\)z - \(\frac{2}{3}\) |