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Solve -5a - 9a = -a + 2x + 5 for a in terms of x.
| -10x + 2 | |
| -2x - 3 | |
| -2\(\frac{3}{4}\)x - 1\(\frac{1}{4}\) | |
| 3x - \(\frac{1}{3}\) |
To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.
-5a - 9x = -a + 2x + 5
-5a = -a + 2x + 5 + 9x
-5a + a = 2x + 5 + 9x
-4a = 11x + 5
a = \( \frac{11x + 5}{-4} \)
a = \( \frac{11x}{-4} \) + \( \frac{5}{-4} \)
a = -2\(\frac{3}{4}\)x - 1\(\frac{1}{4}\)
A cylinder with a radius (r) and a height (h) has a surface area of:
4π r2 |
|
2(π r2) + 2π rh |
|
π r2h2 |
|
π r2h |
A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.
Solve for c:
8c - 3 > \( \frac{c}{9} \)
| c > 2\(\frac{4}{5}\) | |
| c > 2\(\frac{13}{16}\) | |
| c > \(\frac{27}{71}\) | |
| c > 1\(\frac{1}{41}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
8c - 3 > \( \frac{c}{9} \)
9 x (8c - 3) > c
(9 x 8c) + (9 x -3) > c
72c - 27 > c
72c - 27 - c > 0
72c - c > 27
71c > 27
c > \( \frac{27}{71} \)
c > \(\frac{27}{71}\)
Solve for z:
z2 - 4 = 0
| 9 or 6 | |
| -4 or -9 | |
| 2 or -2 | |
| 4 or -9 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
z2 - 4 = 0
(z - 2)(z + 2) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (z - 2) or (z + 2) must equal zero:
If (z - 2) = 0, z must equal 2
If (z + 2) = 0, z must equal -2
So the solution is that z = 2 or -2
What is 2a + 8a?
| 16a | |
| a2 | |
| 10 | |
| 10a |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
2a + 8a = 10a